diff --git a/is/UB1/ISUB1.tex b/is/UB1/ISUB1.tex
index f2f73da..59bd46b 100644
--- a/is/UB1/ISUB1.tex
+++ b/is/UB1/ISUB1.tex
@@ -6,7 +6,7 @@
 \usepackage[utf8]{inputenc} %Umlaute & Co
 \usepackage{hyperref} %Links
 \usepackage{ifthen} %ifthenelse
-
+\usepackage{enumerate}
 
 \usepackage{algpseudocode} %Pseudocode
 \usepackage{dsfont} % schöne Zahlenräumezeichen
@@ -55,9 +55,9 @@
 \end{minipage}
 \vspace{1cm}
 \begin{center}
-{\Large\bf Blatt #1}
+{\Large\bf Sheet #1}
 
-{(Abgabe #3)}
+{(Hand in #3)}
 \end{center}
 }
 
@@ -74,21 +74,33 @@
 \else
 \fi
 
-\indent\textbf{Execise \arabic{n}: #1} (#2 Punkte)\\}
+\indent\textbf{Exercise \arabic{n}: #1} (#2 Punkte)\\}
 
 
 
 
 \begin{document}
     %\header{BlattNr}{Tutor}{Abgabedatum}{Vorlesungsname}{Namen}{Semester}{Anzahl Aufgaben}
-    \header{1}{}{2015-04-22}{Intelligent Systems}{\textit{Maximus Mutschler}\\ \textit{Jan-Peter Hohloch}
+    \header{1}{}{2015-04-22}{Intelligent Systems I}{\textit{Maximus Mutschler}\\ \textit{Jan-Peter Hohloch}
     }{SS 15}{4}
     \vspace{1cm}
     \Aufgabe{Python}{4}
         done
-    \Aufgabe{Poker}
+    \Aufgabe{Poker}{2+2+4=8}
         \begin{enumerate}[1.]
-            \item
+            \item possible hands: ${52 \choose 5}=2598960$\\
+                hands with exaclty one pair: ${13\choose 1}\cdot{4\choose 2}\cdot {12\choose 3}\cdot 4^3=1098240$\\
+                $\mathds{P}(1\ pair)=\frac{1098240}{2598960}=\frac{352}{833}\approx 0.423$
+            \item hands with exaclty two pairs: ${13\choose 2}{4\choose 2}^2\cdot 11\cdot 4=123552$\\
+            $\mathds{P}(2\ pairs)=\frac{123552}{2598960}=\frac{198}{4165}\approx 0.0475$
+            \item \begin{enumerate}[(a)]
+                \item hands with exaclty two pairs without Spades: ${13\choose 2}{3\choose 2}^2\cdot 11\cdot 3=23166$\\
+                $\mathds{P}(2\ pairs|\neg Spades)=\frac{23166}{2598960}=\frac{297}{33320}\approx 0.00891$
+                \item $A:=2\ pairs,\ B:=\neg Spades$\\
+                $P(A|B)=\frac{P(B|A)P(A)}{P(B)}$\\
+                $P(A)=\frac{198}{4165},\ P(B)=\frac{39}{52}\cdot\frac{38}{51}\cdot\frac{37}{50}\cdot\frac{36}{49}\cdot\frac{35}{48}=\frac{2109}{9520}$\\
+                $P(B|A)=?$%TODO
+            \end{enumerate}
         \end{enumerate}
 
 \end{document}