diff --git a/is/UB4/ISUB4.pdf b/is/UB4/ISUB4.pdf
index 49e24e8..bc26f26 100644
--- a/is/UB4/ISUB4.pdf
+++ b/is/UB4/ISUB4.pdf
Binary files differ
diff --git a/is/UB4/ISUB4.tex b/is/UB4/ISUB4.tex
index f17f27f..c2ab9db 100644
--- a/is/UB4/ISUB4.tex
+++ b/is/UB4/ISUB4.tex
@@ -124,6 +124,7 @@
                       1,  |X^T_iY_i|><\sqrt{\lambda}\\
                     \end{cases}
                      \end{math}
+                     It's obviously the wrong solution, but maybe a right attempt.
             \end{enumerate}
             \item \begin{enumerate}
                 \item \includegraphics[width=0.4\textwidth]{gsoft.png}
diff --git a/mr/Ub4/assignment04.pdf b/mr/Ub4/assignment04.pdf
new file mode 100644
index 0000000..12df66a
--- /dev/null
+++ b/mr/Ub4/assignment04.pdf
Binary files differ
diff --git a/mr/Ub4/mr4.pdf b/mr/Ub4/mr4.pdf
index e718668..875a3bf 100644
--- a/mr/Ub4/mr4.pdf
+++ b/mr/Ub4/mr4.pdf
Binary files differ
diff --git a/mr/Ub4/mr4.tex b/mr/Ub4/mr4.tex
index 18db691..fe0dc46 100644
--- a/mr/Ub4/mr4.tex
+++ b/mr/Ub4/mr4.tex
@@ -117,12 +117,17 @@
 			 0 \\ 0\\ -g
 			 \end{pmatrix}
 			$
-			\item $^ba_m = ^bg+^ba_l\\
+			\item 
+			$^ba_m = ^bg+^ba_l\\
 			$
 			if  $ ^ba_m=0$ \\
 			$
 			^ba_l = -^bg
 			$
+			\color{red}\\
+			$^ba_m = ^ba_l-^bg\\
+				^ba_l = ^bg$
+			\color{black} 
 			\item static $\Rightarrow ^ba_l=0$\begin{align*}
 			^ba_m &= b_g+^ba_l\\ &=  ^b\mathbf{R}_w \cdot \begin{pmatrix}
 			0 \\ 0\\ -g
@@ -134,7 +139,13 @@
 			^ba_{m,x}&=	\sin(\theta)g \\
 			\theta &= \sin^{-1}(\frac{^ba_{m,x}}{g})\\
 			^ba_{m,y} &= -g\cdot \sin(\phi)\cdot \sqrt{1-\left(\frac{^ba_x}{g}\right)^2} \\
-			\phi&= \sin^{-1} \left(-\frac{^ba_y}{g*\sqrt{1-\left(\frac{^ba_x}{g}\right)^2}}\right)
+			\phi&= \sin^{-1} \left(-\frac{^ba_y}{g*\sqrt{1-\left(\frac{^ba_x}{g}\right)^2}}\right)\\
+				\color{red}\\
+				\dfrac{a_y}{a_z} &= \frac{C_\Theta S_\Phi g}{C_\Theta C_\Phi g} \\
+				&= \dfrac{S_\Phi}{C_\Phi}\\
+				&= tan(\Phi)\\
+				\Phi&= tan^{-1}(\dfrac{a_y}{a_z}) 
+				\color{black} 
 			 \end{align*}
 	\end{enumerate}\pagebreak
 	\Aufgabe{}{8}
@@ -172,6 +183,8 @@
         $\Rightarrow \sigma_{a_{model}}=\frac{5}{\beta p_0}\cdot e^{100\beta}\approx 0.42124,\\
         \sigma_{a_{passenger}}=\frac{5}{\beta p_0}\cdot e^{10000\beta}\approx 1.3621$
 	\end{enumerate}
+	\color{red}
+	geht einfacher mit Ansatz von linear abhängigen zufallsvariablen aus den Einführungsfolien