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@@ -112,9 +112,39 @@
 \end{enumerate}
 \Aufgabe{Wi-Fi - Problems}{5+10+5}
 \begin{enumerate}
-    \item bla
-    \item bla
-    \item bla
+    \item Time to transmit one packet and receiving the acknowledgment:
+    \begin{align*}
+      T_1 &= \frac{l_d}{N_d} + \frac{l_a}{N_a} \\
+         &= \frac{12000~bit}{11 \cdot 10^{6} ~Mbit/s} + \frac{112~bit}{1 \cdot 10^{6} ~Mbit/s} \\
+         &= \frac{12}{11} \cdot 10^{-3} + 0.112 \cdot 10^{-3} \\
+         &= 1.203 ms
+    \end{align*}
+    The maximum throuput $D_1$ in $bit/s$ is therefore:
+    \begin{align*}
+      D_1 = (1000 ms / 1.203 ms) * (12000 + 112 bit) = 10.07 \cdot 10^{6} bit/s
+    \end{align*}
+    \item Time to transmit one packet and receving the acknowledgment:
+    \begin{align*}
+      T_2 &= t_{difs} + \frac{\sum_{X=0}^{31}X \cdot t_{slot}}{32} + t_{sifs} + T_1 \\     
+          &= 20 \mu s + 15.5 \mu s + 10 \mu s + 1203 \mu s \\
+          &= 1248.5 \mu s \\
+          &= 1.2485 ms
+    \end{align*}
+    The maximum throughput $D_@$ in $bit/s$ is therefore:
+    \begin{align*}
+      D_2 = (1000 ms / 1.2485 ms) * (12000 + 112 bit) = 9.701 \cdot 10^{6} bit/s
+    \end{align*}
+    \item Time to transmit one packet and receiving the acknowledgment:
+    \begin{align*}
+      T_3 &=  \frac{l_{rts}}{N_a} + \frac{l_{cts}}{N_a} + t_{sifs} + t_{sifs} + T_2 \\
+          &= 160 \mu s + 112 \mu s + 20 \mu s + 1285 ms\\
+          &= 292 \mu s + 1285 \mu s \\
+          &= 1.577ms
+    \end{align*}
+     The maximum throughput $D_@$ in $bit/s$ is therefore:
+     \begin{align*}
+       D_3 = (1000 ms / 1.577 ms) * (12000 + 112 + 160 + 112) = 7.852 \cdot 10^{6} bit/s
+     \end{align*}
 \end{enumerate}
 \Aufgabe{Wi-Fi - CSMA/CA, RTS/CTS}{10+10+10}
 \begin{enumerate}