diff --git a/ex06/kn06.pdf b/ex06/kn06.pdf
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diff --git a/ex06/kn06.tex b/ex06/kn06.tex
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@@ -86,5 +86,46 @@
 %\header{BlattNr}{Tutor}{Abgabedatum}{Vorlesungsname}{Namen}{Semester}{Anzahl Aufgaben}
 \header{6}{}{2015-11-25}{Kommunikationsnetze}{\textit{Jonas Jaszkowic, 3592719}\\\textit{Jan-Peter Hohloch, 3908712}}{WS 15/16}{2}
 \vspace{1cm}
-\Aufgabe{Switching Methods in Communication Networks}{45}\\\\
+\Aufgabe{Switching Methods in Communication Networks\footnote{pictures from slides adjusted to exercise}}{45}
+    \begin{enumerate}
+        \item Circuit switching:
+        \begin{itemize}
+            \item Setup time: 3 nodes to find: $3\cdot 3.1s=9.3s$
+            \item Data Transmission Time: $\frac{80000 bit}{4800 bit/s}+3\cdot 0.02s=\frac{50}{3}s+0.06s \approx 16.7s$
+            \item Teardown time: %TODO: not sure whether this is right/necessary
+                nothing given, assume: $0s$
+            \item[$\rightarrow$] Transmission time: $\approx 27s$
+            \includegraphics[width=.5\textwidth]{circuitSwitching.png}
+        \end{itemize}
+        \item Message switching:
+        \begin{itemize}
+            \item One message containing $80000bit+400 bit=80400 bit$
+            \item Setup: no setup times given so we assume datagram switching with one message
+            \item Data transmission: $\frac{80400bit}{4800bit/s}+ 3\cdot 2\cdot 0.02s= 16.75 s+0.12s\approx 16.9s$
+            \item[$\rightarrow$] Transmission time $\approx 16.9s$
+            \includegraphics[width=.5\textwidth]{messageSwitching.png}
+        \end{itemize}
+        \item Package switching:
+        \begin{itemize}
+            \item 20 packages ($\frac{10000}{500}$) containing $500Byte+50Byte=4400bit$
+            \item Setup: no setup times given so we assume datagram switching
+            \item Data transmission: $20\cdot \left(\frac{4400bit}{4800bit/s}+ 3\cdot 2\cdot 0.02s\right) \approx 20\cdot (0.9s+0.12s)\approx 20s$
+            \item[$\rightarrow$] Transmission time $\approx 20s$\vspace{-12pt}\\
+            Picture for each packet:
+            \hfill\includegraphics[width=.5\textwidth]{messageSwitching.png}
+        \end{itemize}
+    \end{enumerate}
+\Aufgabe{Switches}{55}\\
+    Let $i=1,...,5$, in=out=$10^i$
+    \begin{enumerate}
+        \item There are $10^{2i}$ crosspoints (in $\times$ out)
+        \item At maximum there are $10^i$ crosspoints active simultaneously ($\min$(in,out))
+        \item %TODO
+        \item $n$ for minimal number of crosspoints: $\left\lceil \sqrt{\frac{10^i}{2}}\right\rceil=3,8,23,71,224$\\
+        $k\geq 2n-1$ : $k=5,15,45,141,447$
+        \item We use the minimal number of crosspoints above:\\
+        $C_{N,opt}=\frac{N}{n}\cdot n\cdot k + k\cdot \frac{N}{n}\cdot\frac{N}{n}+ \frac{N}{n}\cdot k\cdot n\\
+        =153,5337,175043,5617042,178486160$
+        \item %TODO
+    \end{enumerate}
 \end{document}
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